String.split method in Java accepts RegularExpressions

Regex.Split method in .Net has similar behavior, but there are some differences:

• Delimiters should be defined as non-capturing groups. '(?:)' rather than '()'

• It may return an empty string as the last item !?

We replace call to String.split with Helpers.Regex rather than default System.Text.RegularExpressions.Regex class.

This class contains a Split method which hides differences explained above:

public static string[] Split(string input, string pattern)
{
	//Replace with non-capturing group
	int pIndex = pattern.IndexOf("(");
	while (pIndex != -1 && pIndex != pattern.Length - 1)
	{
		if (pattern[pIndex + 1] != '?')
			pattern = pattern.Insert(pIndex + 1, "?:");
		pIndex = pattern.IndexOf("(", pIndex + 1);
	}

	string[] parts = System.Text.RegularExpressions.Regex.Split(input, pattern);

	ArrayList list = new ArrayList();
	for (int i = 0; i < parts.Length - 1; i++)
		list.Add(parts[i]);
	if (parts[parts.Length - 1] != "")
		list.Add(parts[parts.Length - 1]);

	return (string[]) list.ToArray(typeof(string));
}

See also HelperClass? if you want to add helper classes to Janett.
See also Mapping as for how to map methods to helper classes.